四年级下册方程式计算题500道

体育作者 / 骚皮 / 2026-04-05 20:03
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设x由题意得:1.2x +6=6.6解得x=0.5解方程依据1、移项变号:把方程中的某些项带着前面的符号从方程的一边移到另一边,并且加变减

设x

由题意得:1.2x +6=6.6

解得x=0.5

解方程依据

1、移项变号:把方程中的某些项带着前面的符号从方程的一边移到另一边,并且加变减,减变加,乘变除以,除以变乘。

2、等式的基本性质:

(1)等式两边同时加(或减)同一个数或同一个代数式,所得的结果仍是等式。用字母表示为:若a=b,c为一个数或一个代数式。

(2)等式的两边同时乘或除以同一个不为0的数,所得的结果仍是等式。用字母表示为:若a=b,c为一个数或一个代数式(不为0)。

北师大版四年级下册数学 60道方程题、120道简算题(难)40计算

1.某小学三.四.五年级共种树585棵,四年级棵数是五年级的1/5,三年级种树是五年级的3/4,三个年级各种树多少棵?2.某年七月分的降雨天比晴天少8/11,阴天数是晴天的3/22,这个月雨天有多少天?3.某校五年级共有学生152人,选出男生的1/11和5名女生一起参加数学竞赛,剩下的同学正好相等,这个班有男女同学各多少人?4.有两根铁丝长44米,若把第一根截去1/5,第二根接上2.8米则两根相等,两根原来各长多少米?

答:三年级是:3/4*300=225棵,四年级是:300*1/5=60棵,五年级是300棵

2某人从家骑自行车到火车站,如果每小时行15千米,那么可以比火车开车时间提前15分钟到达,如果每小时行9千米,则要比开车时间晚15分钟到达,现在打算比开车时间早10分钟到达,每小时应行多少千米?

答:二地的距离是:15*[1-15/60]=11。25千米

那么要早到10分,一小时应行:11。25/[1-10/60]=13。5千米

3食堂买来面粉和大米,面粉的重量是大米的两倍,每天吃15千克大米,20千克面粉,几天后大米全部吃完,面粉还剩80千克,这个食堂买来大米和面粉各多少千克?

解:设大米X千克,那么面粉为2X千克,则时间为X/15天,所以有20*(X/15)+80=2X,解得X=120.所以大米120千克,面粉240千克

下面的容易一点的

1:甲车行驶10小时,乙车行驶7小时,甲车比乙车多行驶276千米.如果两车的速度相同,求这两列车的速度.(方)

2:陈和张骑自行车从同一地点同时向相反方向骑.0.5小时后相距12.5千米.陈每小时行驶12千米,张每小时行多少千米?(方)

3:家具厂卖出书柜个数是五X柜的五分之一,卖出的书柜比五X柜少120个,卖出书柜和五X柜各多少?(方)

4:做一个容织是60平方分米的长方体铁皮箱,底面的长是4分米,宽是3分米,高是多少?(方)

5:师傅加工零件80个,比徒弟加工的2陪少10个.徒弟加工多少个?(方)

6:徒弟加工零件45个,比师傅的二分之一多5个.师傅加工多少个?(方)

答案:

1.甲X乙Y

10X-7Y=267

10/X+7/Y=1

2.张X

(12+X)*0.5=12.5

3.书柜X五X柜Y

X=五分之一*Y

X=Y-120

4.高X

4*3*X=60

5.徒弟X

2X-10=80

6.师傅X

二分之一*X+5=45

希望你满意~!^_^~~!

20道解方程练习题(要有答案)

最佳答案

125÷(50÷8)

=125÷50×8

=125×8÷50

=1000÷50

=20

7.2×1.02

=7.2×(1+0.02)

=7.2×1+7.2×0.02

=7.2+0.144

=7.344

9又9/16÷9

=(9+9/16)÷9

=9÷9+9/16÷9

=1+1/16

=17/16

(90+1/88)×1/89

=(90×88+1)/88×1/89

=[(89+1)×(89-1)+1]/88×1/89

=[89^2-1^2+1]/88×1/89

=89^2/88×1/89

=89/88

(1/3-1/4)+(1/4-1/5)+(1/5-1/6)

=1/3-1/4+1/4-1/5+1/5-1/6

=1/3-1/6

=1

7.6×1/2÷[1.9-1.9×(1.9-1.9)]

=7.6×1/2÷(1.9-0)

=3.8÷1.9

=2

1又1/6×1又1/7×1又1/8×1又1/9×1又1/10

=7/6×8/7×9/8×10/9×11/10

=11/6

3.26×[1÷(1/10-9/100)]

=3.26×[1÷(10/100-9/100)]

=3.26×(1÷1/100)

=3.26×100

=326

(2.5+2.5+2.5+2.5)×25×8

=(2.5×4)×25×4×2

=10×100×2

=2000

(6.9×0.125×1.75)÷(2.3×1/8×1/4)

=6.9×0.125×1.75÷2.3÷1/8÷1/4

=6.9÷2.3×0.125×8×1.75×4

=3×1×7

=21

[5-(0.5×9又1/2+1/2×1/2)]÷8/21

=[5-(1/2×19/2+1/2×1/2)]×21/8

=[5-1/2×(19/2+1/2)]×21/8

=(5-1/2×10)×21/8

=(5-5)×21/8

=0

(12又13/25+7又8/17)×2.5+(9又9/17+10又12/25)2又1/2

=(12又13/25+7又8/17)×2.5+(9又9/17+10又12/25)×2.5

=(12又13/25+7又8/17+9又9/17+10又12/25)×2.5

=(23+17)×2.5

=40×2.5

=100

1又2/3×[7又5/6+(4.125-4又1/8)-4又5/6]

=5/3×[7又5/6-4又5/6+(4又1/8-4又1/8)]

=5/3×(3+0)

=5

8又17/23+5又1/4-6又17/23+0.75

=(8又17/23-6又17/23)+(5.25+0.75)

=2+6

=8

(5又5/9-0.8+2又4/9)×12.5

=(5又5/9+2又4/9-0.8)×12.5

=(8-0.8)×12.5

=8×12.5-0.8×12.5

=100-10

=90

2.25×3/7×0.4×2又1/3

=2.25×0.4×3/7×7/3

=0.9×1

=0.9

0.91÷4/5+1.25×1.09

=0.91×5/4+5/4×1.09

=5/4×(0.91+1.09)

=5/4×2

=2.5

9又2000/2001×1949

=(10-1/2001)×1949

=10×1949-1/2001×1949

=19490-1949/2001

=10489+(1-1949/2001)

=10489+52/2001

=10489又52/2001

24×51/43+51×19/43

=24×51/43+19×51/43

=(24+19)×51/43

=43×51/43

=51

13.76-(7/12+1.76+1又5/12)

=13.76-[1.76+(7/12+1又5/12)]

=13.76-1.76-2

=12-2

=10

19.98×37-199.8×1.9+1998×0.82

=199.8×3.7-199.8×1.9+199.8×8.2

=199.8×(3.7-1.9+8.2)

=199.8×10

=1998

0.32×6.7+3.2×0.43-0.32

=3.2×0.67+3.2×0.43-3.2×0.1

=3.2×(0.67+0.43-0.1)

=3.2×1

=3.2

2.5×12.5×32-32-563

=2.5×12.5×4×8-(32+563)

=(2.5×4)×(12.5×8)-595

=10×100-595

=1000-595

=405

9又3/4-15/19-2/19×2

=9又3/4-(15/19+4/19)

=9又3/4-1

=8又3/4

(2/3+1/5)+(2/3-12/17)-(1/5+5/17)

=2/3+1/5+2/3-12/17-1/5-5/17

=(2/3+2/3)+(1/5-1/5)-(12/17+5/17)

=4/3+0-1

=1/3

(4/9+5/13+5/9+8/13)×(1-91/100)

=[(4/9+5/9)+(5/13+8/13)]×9/100

=(1+1)×9/100

=9/50

[(1/4-1/4÷2)×8/13+1÷6又1/2]÷0.01

=[(1/4-1/8)×8/13+1×2/13]×100

=(1/8×8/13+2/13)×100

=3/13×100

=300/13

(3+3/4÷3/4+3)-(7×1/6÷7×1/6)

=(3+1+3)-(1/6×1/6)

=7-1/36

=6又35/36

5-[1又1/3-(2.5-1又2/3)]÷0.125

=5-(1又1/3+1又2/3-2.5)×8

=5-(3-0.5)×8

=5-0.5×8

=5-4

=1

14.8×6.3+46.5×4.5+8.3×3.7+0.465×550-6.3×6.5

=14.8×6.3-6.3×6.5+46.5×4.5+46.5×5.5+8.3×3.7

=6.3×(14.8-6.5)+46.5×(4.5+5.5)+(8+0.3)×3.7

=6.3×8+46.5×10+8×3.7+0.3×3.7

=8×(6.3+3.7)+465+1.11

=80+466.11

=546.11

(78.6-0.786×25+0.75×21.4)÷15×2001

=(78.6-78.6×0.25+0.75×21.4)÷15×2001

=[78.6×(1-0.25)+0.75×21.4)÷15×2001

=(78.6×0.75+0.75×21.4)÷15×2001

=0.75×(78.6+21.4)÷15×2001

=0.75×100÷15×2001

=75÷15×2001

=5×2001

=10005

(49/90×7/20+1.65×49/90-49/90)÷[2又14/15-(4-2又14/15)]

=49/90×(0.35+1.65-1)÷(2又14/15+2又14/15-4)

=49/90×1÷(4又28/15-4)

=49/90×15/28

=7/24

(1又1/1998×8.12+5又31/75÷2/3×8又1997/1998)÷4又11/48

=(1又1/1998×8又12/100+406/75×3/2×8又1997/1998)÷4又11/48

=(1又1/1998×203/25+203/25×8又1997/1998)÷4又11/48

=203/25×(1又1/1998+8又1997/1998)÷4又11/48

=203/25×10÷203/48

=10/25×48

=96/5

2÷(2又2/9×4/5+2又2/9×6.2-5.8×2又2/9)×9/20

=2÷[2又2/9×(4/5+6.2-5.8)]×9/20

=2÷(20/9×1.2)×9/20

=2×3/8×9/20

=27/80

1又2/3-[(3.62×2/15+6.38÷7又1/2)×1.82-1又1/3×0.82]

=1又2/3-[(3.62×2/15+6.38×2/15)×1.82-1又1/3×0.82]

=1又2/3-[2/15×(3.62+6.38)×1.82-4/3×0.82]

=5/3-[2/15×10×1.82-4/3×0.82]

=5/3-4/3×(1.82-0.82)

=5/3-4/3

=1/3

12÷(6又7/10×0.8+6又7/10×6又1/2-4/5×6又7/10+2又1/3×6又7/10)

=12÷[6又7/10×(0.8+13/2-0.8+7/3)]

=12÷[67/10×53/6]

=12÷[(60+7)×(60-7)/60]

=12÷[(3600-49)/60]

=720/3551

38×1又1/1999+8又1998/1999×1又1/18÷1/36

=38×1又1/1999+8又1998/1999×19/18×36

=38×(1又1/1999+8又1998/1999)

=38×10

=380

9.75+99.75+999.75+9999.75

=10-0.25+100-0.25+1000-0.25+10000-0.25

=(10+100+1000+10000)-0.25×4

=11110-1

=11109

1/2001+2/2001+3/2001+4/2001+…+2001/2001

=(1+2+3+...+2001)/2001

=[(1+2001)×2001÷2]/2001

=1001×2001/2001

=1001

10101/131313×91

=10101/(13×10101)×(7×13)

=7

112又14/23÷37

=(112+14/23)÷37

=(14×8+14×1/23)÷37

=14×8又1/23÷37

=14×185×1/37

=14×5

=70

125×25×3232×69

=125×25×(4×8×101)×69

=(125×8)×(25×4)×(101×69)

=1000×100×6969

=696900000

3333×3333+9999×8889

=1111×3×3333+9999×8889

=1111×9999+9999×8889

=9999×(1111+8889)

=9999×10000

=99990000

9999×7+1111×37

=1111×9×7+1111×37

=1111×(63+37)

=1111×100

=111100

999×778+333×666

=999×778+333×3×222

=999×(778+222)

=999×1000

=999000

20012001÷19971997

=2001×10001÷(1997×10001)

=2001÷1997

=2001/1997

20022002÷20012001

=2002×10001÷(2001×10001)

=2002÷2001

=2002/2001

97×2000-96×2001

=97×(2001-1)-96×2001

=97×2001-97-96×2001

=(97-96)×2001-97

=2001-97

=1904

1989×1999-1988×2000

=1989×(2000-1)-1988×2000

=1989×2000-1989-1988×2000

=(1989-1988)×2000-1989

=2000-1989

=11

5/21×2/7+2又19/21×5/7+(1-2/7)

=5/7×2/21+2又19/21×5/7+5/7

=5/7×(2/21+2又19/21+1)

=5/7×4

=20/7

1-1/2-1/4-1/8-…-1/128

=1/2-1/4-1/8-...-1/128

=1/4-1/8-...-1/128

=1/8-...-1/128

⑤哖级嘀吖!吥崾打错题……谢谢各莅了哈、最好媞侑答案吖~~记住⑤哖级!!!!谢哈!!

问题补充:补充①下哈~~~ 吥媞方程应用题菈! 媞方程计算题菈! 対吥起哈 、徔偂没提醒~~ 请苋谅哈、

提问者: 尛俽HA - 实习生 一级 最佳答案7χ-2×9=80 6x-4x=20.2 (χ+12)÷4=4.5

6x-0.4×6 = 9.6 118-2×( 4.1 + X ) = 55 4x +80 = 160

9.6÷X = 0.8 4.8-X = 3×( X + 6 ) 4.3X-1.5 + 3.2X = 4.5

483回答者: 123.114.135.* 2009-7-29 14:56

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提问者对于答案的评价:τheńk yōū

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